Question
Reduce the following rational numbers in its lowest form: $\frac{-60}{72}$
✓
Answer
$\frac{-60}{72}$ can be written as $=\frac{-60+12}{72+12}$
$[$dividing numerator and denominator by $HCF$ of $60$ and $72$ i.e. $12]$
$=\frac{-60\times\frac{1}{12}}{72\times\frac{1}{12}}$
$\Big[\because\text{Reciprocal of }12=\frac{1}{12}\Big]$
$=\frac{-5}{6},$ which is the lowest form.
$[$dividing numerator and denominator by $HCF$ of $60$ and $72$ i.e. $12]$
$=\frac{-60\times\frac{1}{12}}{72\times\frac{1}{12}}$
$\Big[\because\text{Reciprocal of }12=\frac{1}{12}\Big]$
$=\frac{-5}{6},$ which is the lowest form.
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