Question
Reduce the following fractions into its simplest form:
$\frac{48}{60}$
$\frac{48}{60}$
✓
Answer
Here, numerator = 84 and denominator = 98
Factors of 84 are 1, 2, 3, 4, 6, 7, 12, 14, 21, 42 and 84
Factors of 98 are 1, 2, 7, 14, 49 and 98
Common factors of 84 and 98 are 1, 2, 7 and 14
H.C.F. of 84 and 98 is 14
$\therefore\frac{48}{60}=\frac{48\div12}{60\div12}=\frac{4}{5}$
Hence, the simplest form of $\frac{48}{60}$ is $\frac{4}{5}$.
Factors of 84 are 1, 2, 3, 4, 6, 7, 12, 14, 21, 42 and 84
Factors of 98 are 1, 2, 7, 14, 49 and 98
Common factors of 84 and 98 are 1, 2, 7 and 14
H.C.F. of 84 and 98 is 14
$\therefore\frac{48}{60}=\frac{48\div12}{60\div12}=\frac{4}{5}$
Hence, the simplest form of $\frac{48}{60}$ is $\frac{4}{5}$.
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