Question
Reduce the following fractions to its lowest term (simplest form): $\frac{42}{28}$
✓
Answer
$\frac{42}{28}$
Factors of $42$ are $1, 2, 3, 6, 7, 14, 21, 42$
Factors of $28$ are $1, 2, 4, 7, 14, 28$
Common factors of $42$ & $28$ are $1, 2, 7$ and $14$
So, $HCF = 14$
Divide both the numerator & denominator by $14$
$\frac{42\div14}{28\div14}=\frac{3}{2}$
Therefore, the simplest form obtained is $=\frac{3}{2}$
Factors of $42$ are $1, 2, 3, 6, 7, 14, 21, 42$
Factors of $28$ are $1, 2, 4, 7, 14, 28$
Common factors of $42$ & $28$ are $1, 2, 7$ and $14$
So, $HCF = 14$
Divide both the numerator & denominator by $14$
$\frac{42\div14}{28\div14}=\frac{3}{2}$
Therefore, the simplest form obtained is $=\frac{3}{2}$
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