Question
Reduce the following fractions to the lowest terms:$\frac{161}{207}$
✓
Answer
$\frac{161}{207}$ To reduce the given fraction to its lowest terms,
we will divide the numerator and the denominators by their $HCF.$
Now, we will find the $HCF$ of $161$ and $207.$
$\therefore HCF = 23$
Dividing the numerator and the denominators by the $HCF,$
we get: $\frac{161\div23}{207\div23}=\frac79$
we will divide the numerator and the denominators by their $HCF.$
Now, we will find the $HCF$ of $161$ and $207.$
$\therefore HCF = 23$
Dividing the numerator and the denominators by the $HCF,$
we get: $\frac{161\div23}{207\div23}=\frac79$
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