Question
Reduce to standard form: $\frac{-3}{-15}$
✓
Answer
The $HCF$ of $3$ and $15$ is $3.$
Hence, $\frac{-3}{-15}=\frac{-3 \div(-2)}{-15 \div(-3)}=\frac{1}{5}$
Hence, $\frac{-3}{-15}=\frac{-3 \div(-2)}{-15 \div(-3)}=\frac{1}{5}$
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