MCQ
Reduction of carboxylic acids gives
- AAlcohol with hydrogen in presence of palladium
- ✓Alcohol with $LiAl{H_4}$
- CAldehyde with $LiAl{H_4}$
- DAlcohol with $2HI(P)$
✓
Answer
Correct option: B.
Alcohol with $LiAl{H_4}$
b
(b)$C{H_3}COOH\xrightarrow{{LiAl{H_4}}}C{H_3}C{H_2}OH$
(b)$C{H_3}COOH\xrightarrow{{LiAl{H_4}}}C{H_3}C{H_2}OH$
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