MCQ
Reduction of carboxylic acids gives
- AAlcohol with hydrogen in presence of palladium
- ✓Alcohol with $LiAl{H_4}$
- CAldehyde with $LiAl{H_4}$
- DAlcohol with $2HI(P)$
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$\begin{array}{*{20}{c}}
{{C_2}{H_5}MgBr + {H_2}C - C{H_2}\xrightarrow{{{H_2}O}}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\backslash \,\,\,\,/} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}
\end{array}A$
$(A)$ $\mathrm{NH}_4 \mathrm{NO}_3$ $(B)$ $\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7$ $(C)$ $\mathrm{Ba}\left(\mathrm{N}_3\right)_2$ $(D)$ $\mathrm{Mg}_3 \mathrm{~N}_2$
