MCQ
Reduction of carboxylic acids gives
- AAlcohol with hydrogen in presence of palladium
- ✓Alcohol with $LiAl{H_4}$
- CAldehyde with $LiAl{H_4}$
- DAlcohol with $2HI(P)$
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Reason : Red phosphorus consists of $P_4$ tetrahedral units linked to one another to form linear chains.
$(I)\,\,HCHO$ $ (II)\,\,CH_3CHO$
$(III)$ Acetone $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{(IV)\,\,\,Et - C - Et}
\end{array}$
$(A)\,\, HCHO$ $(B) \,\,CH_3COCH_3$
$(C)\,\,PhCOCH_3$ $(D)\,\ PhCOPh$