Question
Reflexive and symmetric but not transitive.
| It is clear that x is friend of x. | $\therefore$ | R is reflexive. |
| Also x is friend of y and y is friend of x. | $\therefore$ | R is symmetric. |
| Also if x is friend of y and y is friend of z then | ||
| x cannot be friend of z. | $\therefore$ | R is not transitive. |
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