Question
Relative lowering of vapour pressure.

Answer

Relative lowering of vapour pressure: If $P_0$ and $P$ are the respective vapour pressures of a pure liquid (solvent) and the solution containing a non-volatile solute then $P < P _0$. Hence, $P _0- P$ represents the lowering of the vapour pressure due to addition of a nonvolatile solute.
$\therefore$ Relative lowering of vapour pressure $=\frac{P_0-P}{P_0}=\frac{\Delta P}{P_0}$

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