Question
Remainder when $64^{32^{12}}$ is divided by $9$ is equal to $...........$
✓
Answer
Let $32^{32}= t$
$64^{32^{12}}=64^t$
$=8^{2 t}$
$=(9-1)^{2 t}$
$=9 k+1$
Hence remainder $=1$
$64^{32^{12}}=64^t$
$=8^{2 t}$
$=(9-1)^{2 t}$
$=9 k+1$
Hence remainder $=1$
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