Question
 Remainder when $ 64^{32^{32}}$  is divided by  $9$ is equal to .........................

Answer

d
Let $32^{32}=\mathrm{t}$

$ 64^{32^{32}}=64^t=8^{2 t}=(9-1)^{2 \mathrm{t}} $

$ =9 \mathrm{k}+1$

Hence remainder $=1$

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