MCQ
Remainder when $ 64^{32^{32}}$ is divided by $9$ is equal to .........................
- A$5$
- B$4$
- C$8$
- ✓$1$
$ 64^{32^{32}}=64^t=8^{2 t}=(9-1)^{2 \mathrm{t}} $
$ =9 \mathrm{k}+1$
Hence remainder $=1$
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$f ( x )=(3-\sin (2 \pi x )) \sin \left(\pi x -\frac{\pi}{4}\right)-\sin \left(3 \pi x +\frac{\pi}{4}\right)$
If $\alpha, \beta \in[0,2]$ are such that $\{x \in[0,2]: f(x) \geq 0\}=[\alpha, \beta]$, then the value of $\beta-\alpha$ is. . . . . . . . .