Question
Represent $\sqrt{5}$ on the number line.
✓
Answer
Draw a number line as shown.
On the number line, take point $O$ corresponding to zero.
Now take point $A$ on number line such that $OA = 2$ units.
Draw perpendicular $AZ$ at $A$ on the number line and cut$-$off arc $AB = 1$ unit.
By Pythagoras Theorem,
$OB^2 = OA^2 + AB^2$
$= 2^2 + 1^{2 }= 4 + 1 = 5$
$\Rightarrow\text{OB}=\sqrt{5}$
Taking $O$ as centre and $\text{OB}=\sqrt{5}$ as radius draw an arc cutting real line at $C$.
Clearly, $\text{OC}=\text{OB}=\sqrt{5}$
Hence$, C$ represents $\sqrt{5}$ on the number line.
On the number line, take point $O$ corresponding to zero.
Now take point $A$ on number line such that $OA = 2$ units.
Draw perpendicular $AZ$ at $A$ on the number line and cut$-$off arc $AB = 1$ unit.
By Pythagoras Theorem,
$OB^2 = OA^2 + AB^2$
$= 2^2 + 1^{2 }= 4 + 1 = 5$
$\Rightarrow\text{OB}=\sqrt{5}$
Taking $O$ as centre and $\text{OB}=\sqrt{5}$ as radius draw an arc cutting real line at $C$.
Clearly, $\text{OC}=\text{OB}=\sqrt{5}$
Hence$, C$ represents $\sqrt{5}$ on the number line.
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