STD 11 - 14. Breathing and exchange in gases — NEET STD 11 Science — Question

$HC O _{3}^{-}$and $H ^{+}$. At the alveolar site, where $\rho CO _{2}$ is low, the reaction proceeds in the opposite direction, leading to the formation of $H _{2} O$ and $CO _{2} .$ Thus, $CO _{2}$ gets trapped as bicarbonate at the tissue level and transported to the alveoli and released as $CO _{2}$