RN{H_2} reacts with {C_6}{H_5}S{O_2}Cl in aqueous KOH to give a clear solution. On acidification a precipitate is obtained which is due to the formation of

Q: $RN{H_2}$ reacts with ${C_6}{H_5}S{O_2}Cl$ in aqueous $KOH$ to give a clear solution. On acidification a precipitate is obtained which is due to the formation of

c (c) ${{C}_{6}}{{H}_{5}}S{{O}_{2}}Cl+RN{{H}_{2}}\to RNHS{{O}_{2}}{{C}_{6}}{{H}_{5}}\xrightarrow{KOH}$ $\underset{\text{soluble in }KOH}{\mathop{RNKS{{O}_{2}}{{C}_{6}}{{H}_{5}}}}\,$

SECTION - A [CHEMISTY - MCQ]

GSEB - English Medium

$RN{H_2}$ reacts with ${C_6}{H_5}S{O_2}Cl$ in aqueous $KOH$ to give a clear solution. On acidification a precipitate is obtained which is due to the formation of

A$R - \mathop {\mathop {{N^ + }}\limits_{|\,\,\,\,}^{|\,\,\,\,} }\limits_{H\,\,\,}^{H\,\,} - S{O_2}{C_6}{H_5}O{H^ - }$
B$R - {N^ - }S{O_2}{C_6}{H_5}{K^ + }$
C$R - NHS{O_2}{C_6}{H_5}$
D${C_6}{H_5}S{O_2}N{H_2}$

Difficult

STD 11 Science
JEE
STD 12 - 9. Amines
Chemistry

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