Sasha solves a linear equation. Her work is shown below 2 x-3 & =… - Vidyadip

Question

Sasha solves a linear equation. Her work is shown below
$\begin{aligned} 2 x-3 & =\frac{x}{2}-5 \\ 2(2 x-3) & =x-5 \ldots \ldots \text { Step } 1 \\ 4 x-6 & =x-5 \ldots \ldots \text { Step } 2 \\ 4 x-x & =6-5 \ldots \ldots \text { Step } 3 \\ 3 x & =1 \ldots \ldots \text { Step } 4 \\ x & =\frac{1}{3}\end{aligned}$
Is Sasha's solution correct? If not, in which step did Sasha make an error?

✓

Answer

No, Sasha's solution is not correct. She did an error in Step 1. She should transpose $\frac{x}{2}$ to LHS and -3 to RHS.

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