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Factorisation — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSFactorisation3 Marks
Question
Satpal solved an algebraic equation as shown below.
Algebraic equation: $(s+4)^2=36+s^2$
Step I $s^2+16+8 s=36+s^2$
Step II $8 s=52$
Step III $s=52 \times 8=132$
Did Satpal solve the equation correctly? Explain your answer.
✓

Answer

Given algebraic equation $(s+4)^2=36+s^2$
Step I Using Identity I on LHS, we get
$
s^2+16+8 s=36+s^2
$
Step II $8 s=36-16=20$
which shows that given Step II does not match with our Step II.
This shows that mistake of adding 16 instead of subtraction was done by Satpal in Step II.
Hence, Step II solved by Satpal was wrong.

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