MCQ
$(\sec 2 A+1) \sec ^2 A=$
  • A
    sec A
  • B
    2 sec A
  • C
    sec 2A
  • 2 sec 2A

Answer

Correct option: D.
2 sec 2A
(D)
$(\sec 2 A+1) \sec ^2 A$
$=\left(\frac{1+\tan ^2 A}{1-\tan ^2 A}+1\right)\left(1+\tan ^2 A\right)$
$=\frac{2\left(1+\tan ^2 A\right)}{1-\tan ^2 A}=2 \sec 2 A$

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