( 2A + 1) ^2 A = - Vidyadip

MCQ

$(\sec 2A + 1){\sec ^2}A = $

A
$\sec A$
B
$2\sec A$
C
$\sec 2A$
✓
$2\sec 2A$

✓

Answer

Correct option: D.

$2\sec 2A$

d
(d) $(\sec 2A + 1){\sec ^2}A $

$= \left( {\frac{{1 + {{\tan }^2}A}}{{1 - {{\tan }^2}A}} + 1} \right)\,(1 + {\tan ^2}A)$

$ = \frac{{2\,(1 + {{\tan }^2}A)}}{{1 - {{\tan }^2}A}}$

$= 2\sec 2A.$

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