MCQ
$(\sec A + \tan A - 1)(\sec A - \tan A + 1) - 2\tan A = $
  • A
    $\sec A$
  • B
    $2\sec A$
  • $0$
  • D
    $1$

Answer

Correct option: C.
$0$
c
(c) $(\sec A + \tan A - 1)(\sec A - \tan A + 1) - 2\tan A$

$ = ({\sec ^2}A - {\tan ^2}A) + \sec A + \tan A - \sec A$$ + \tan A - 1 - 2\tan A = 0$

                                           $( \because {\sec ^2}A - {\tan ^2}A = 1)$

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