MCQ
$\sec ({\rm{cose}}{{\rm{c}}^{ - 1}}x)$ is equal to
  • ${\rm{cosec}}({\sec ^{ - 1}}x)$
  • B
    $\cot x$
  • C
    $\pi $
  • D
    None of these

Answer

Correct option: A.
${\rm{cosec}}({\sec ^{ - 1}}x)$
a
(a) We know that  $sec(cosec-1x) = cosec(sec-1 x)$

$ = \frac{{|x|}}{{\sqrt {{x^2} - 1} }}$, for $|x|\, > \,1$.

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