MCQ
Second ionization potential of $Li, Be$ and $B$ is in the order
  • A
    $Li > Be > B$
  • $Li > B > Be$
  • C
    $Be > Li > B$
  • D
    $B > Be > Li$

Answer

Correct option: B.
$Li > B > Be$
b
Second ionization potential depends on the electron ejection from $Li ^{+}, Be ^{+}$and $B ^{+}$

Electronic configuration for these ions is:

$Li ^{+}: 1 s ^2$

$Be ^{+}: 1 s ^2\, 2 s ^1$

$B ^{+}: 1 s ^2\, 2 s ^2$

For, lithium and boron, electron is to be ejected from fully filled stable shells.

Further, it is difficult to remove electron from is shell of $Li$ because it is closer to the nucleus as compared to $2 s$ shell of $B$. It is much easier to remove electron from $Be$ because it will attain stable electronic configuration after losing this electron.

Thus, order is $Li \,> \,B\, >\, Be$

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