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A given nitrogen-containing aromatic compound $'A'$ reacts with $Sn/HCl,$ followed by $HNO_2$ to give an unstable compound $'B'$. $ 'B',$ on treatment with phenol, forms a beautiful coloured compound $'C'$ with the molecular formula $C_{12}H_{10}N_2O.$ The structure of compound $'A'$ is
Assertion : Acetamide reacts with $Br_2$ in presence of methanolic $CH_3ONa$ to form methyl $N-$ methylcarbamate.
Reason : Methyl isocyanate is formed as an intermediate which reacts with methanol to form methyl $N-$ methylcarbamate.
$1.86\, g$ of aniline completely reacts to form acetanilide. $10 \,\%$ of the product is lost during purification. Amount of acetanilide obtained after purification (in $g$) is ...... $\times 10^{-2}.$