$(ii)$ $O_3^+, O_3$
$(iii)$ $NO_2^-$ or $O_3$
$(iv)$ $X—S—X$ angle in $SOCl_2$ and $SOF_2$
(i) According to Drago's rule, the trend of decreasing bond angle in $\mathrm{NH}_{3}, \mathrm{PH}_{3},$ and $\mathrm{AsH}_{3}$ is :
$\mathrm{NH}_{3}>\mathrm{PH}_{3}>\mathrm{AsH}_{3}$
(ii) $\alpha<\beta$ because lone pair-double repulsion in $\mathrm{O}_{3}$ is greater than single electron-double bond in $\mathrm{O}_{3}^{+}$ .
Also, lone pair-single bond (electron pair) repulsion in $\mathrm{O}_{3}$ is greater than single electronsingle bond repulsion in $\mathrm{O}_{3}^{+}$
(iii) According to Bent's rule, $\mathrm{N}-\mathrm{O}$ bond $(\mathrm{B} . \mathrm{O} \cdot \mathrm{r}=1.5)$ in $\mathrm{N} \mathrm{O}_{2}^{-}$ has more p character than $\mathrm{O}-\mathrm{O}$ bond (B.O. $=1.5)$ in $\mathrm{O}_{3}$. Hence $\alpha<\beta$.
(iv) According to Bent's rule, there is more $\mathrm{p}$ -character in $\mathrm{S}-\mathrm{F}$ bond than in $\mathrm{S}-\mathrm{Cl}$ bond in $\mathrm{SOCl}_{2}$. Hence $\alpha<\beta$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(A)$ The $pH$ of $1 \times 10^{-8}\,M\,HCl$ solution is $8$.
$(B)$ The conjugate base $H _2 PO _4^{-}$is $HPO _4{ }^{2-}$.
$(C)$ $K _{ w }$ increases with increase in temperature.
$(D)$ When a solution of weak monoprotic acid is titrated against a strong base at half neutralisation point, $pH =\frac{1}{2} pK _{ a }$
Choose the correct answer from the option given below.
$(a)$ Heat of combustion reaction
$(b)$ Heat of formation reaction
$(c)$ An exothermic reaction
$(d)$ Not neutralization reaction