$(ii)$ $O_3^+, O_3$
$(iii)$ $NO_2^-$ or $O_3$
$(iv)$ $X—S—X$ angle in $SOCl_2$ and $SOF_2$
(i) According to Drago's rule, the trend of decreasing bond angle in $\mathrm{NH}_{3}, \mathrm{PH}_{3},$ and $\mathrm{AsH}_{3}$ is :
$\mathrm{NH}_{3}>\mathrm{PH}_{3}>\mathrm{AsH}_{3}$
(ii) $\alpha<\beta$ because lone pair-double repulsion in $\mathrm{O}_{3}$ is greater than single electron-double bond in $\mathrm{O}_{3}^{+}$ .
Also, lone pair-single bond (electron pair) repulsion in $\mathrm{O}_{3}$ is greater than single electronsingle bond repulsion in $\mathrm{O}_{3}^{+}$
(iii) According to Bent's rule, $\mathrm{N}-\mathrm{O}$ bond $(\mathrm{B} . \mathrm{O} \cdot \mathrm{r}=1.5)$ in $\mathrm{N} \mathrm{O}_{2}^{-}$ has more p character than $\mathrm{O}-\mathrm{O}$ bond (B.O. $=1.5)$ in $\mathrm{O}_{3}$. Hence $\alpha<\beta$.
(iv) According to Bent's rule, there is more $\mathrm{p}$ -character in $\mathrm{S}-\mathrm{F}$ bond than in $\mathrm{S}-\mathrm{Cl}$ bond in $\mathrm{SOCl}_{2}$. Hence $\alpha<\beta$
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$(I)\,\,Ph-CH=CH-COOH$
$(II)\,\,p-NO_2-C_6H_4-CH=CH-COOH$
$(III)\,\,p-MeO-C_6H_4-CH=CH-COOH$
$(IV)\,\,p-Cl-C_6H_4-CH=CH-COOH$
| $LIST-I$ $(Substances)$ | $LIST-II$ $(Element Present)$ |
| $A$. Ziegler catalyst | $I$. Rhodium |
| $B$. Blood pigment | $II$. Cobalt |
| $C$ .Wilkinson catalyst | $III$. Iron |
| $D$. Vitamin $\mathrm{B}_{12}$ | $IV$. Titanium |
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