- ✓

- B

- C

- D$Ph - I\xrightarrow[\Delta ]{{Cu}}Ph - Ph$




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takes places through the mechanism given below :
$NO + Br _2 \Leftrightarrow NOBr _2 \text { (fast) }$
$NOBr _2+ NO \rightarrow 2 NOBr \text { (slow) }$
The overall order of the reaction is $.....$.
(Given : $K_b$ of water $=0.5\ Kkg/mol$ . ; Atomic mass of $Ca =40$ , $Br =80$)
$2 \mathrm{Fe}^{3+}(\mathrm{aq})+2 \mathrm{I^-}(\mathrm{aq}) \rightarrow 2 \mathrm{Fe}^{2+}(\mathrm{aq})+\mathrm{I}_{2}(\mathrm{aq})$
$\mathrm{E}_{\text {call }}^{\mathrm{e}}=0.24 \mathrm{V}$ at $298\; \mathrm{K}$. The standard Gibbs energy $\left( {{\Delta _r}{{\rm{G}}^ \ominus }} \right)$ of the cell reaction is:
[Faraday constant $\mathrm{F}=96500 \;\mathrm{C} \mathrm{mol}^{-1} $]