- A$CC{l_4}$
- B$C{S_2}$
- C$CHC{l_3}$
- ✓${C_2}{H_5}OH$
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$(I)$ electron affinity of $Y$ is high $(II)$ ionization energy of $X$ is low
$(III)$ lattice energy of $XY$ is high $(IV)$ lattice energy of $XY$ is low
Choose the correct code
$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH = C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{{HBr}}A$
$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH = C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{{HBr + ROOR}}B$
$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH = C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{{NBS}}C$