- A$[Ar]\,\,4s^2\,\,3d^5$ this configuration belongs to $d-$ block
- BMagic No. of $III$ $B$ group is $= 18,\,\,18,\,\,32$
- CIn first transition series total $10$ elements
- ✓All are correct
$III\,\,B$ magic no. $\Rightarrow \,\,18,\,\,18,\,\,32$
First transition $(3d)\Rightarrow $ At. No. $\Rightarrow $ $21 -30$
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$NH_2-CH_2-CH_2-NH_2 +$ $\begin{array}{*{20}{c}}
{COO{C_2}{H_5}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{COO{C_2}{H_5}}
\end{array}$ $\xrightarrow{{Pyridne}}$ $[X]$
$[X]$ will be :
If all products formed in the above reaction undergo reaction with $Br_2(CCl_4)$ individually then number of products formed will be :

$I ^{-}+ ClO _3^{-}+ H _2 SO _4 \longrightarrow Cl ^{-}+ HSO _4^{-}+ I _2$
The correct statement(s) in the balanced equation is/are:
$(A)$ Stoichiometric coefficient of $HSO _4^{-}$is 6 .
$(B)$ lodide is oxidized.
$(C)$ Sulphur is reduced.
$(D)$ $H _2 O$ is one of the products.