MCQ
Select the correct order of bond angle ?
- A$NO_2^+ > NO_2 > NH_4^+$
- B$COF_2 < COCl_2 < COBr_2$ ($X-C-X$ bond angle where $X$ is halogen)
- C$H_2S < SF_2 < SCl_2$
- ✓All of these
✓
Answer
Correct option: D.
All of these
d
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Match List$-I$ with List$-II$:
→|
List$-I$ (Parameter) |
List$-II$ (Unit) |
| $(a)$ Cell constant | $(i)$ $\mathrm{S}\, \mathrm{cm}^{2} \,\mathrm{~mol}^{-1}$ |
| $(b)$ Molar conductivity | $(ii)$ Dimensionless |
| $(c)$ Conductivity | $(iii)$ $\mathrm{m}^{-1}$ |
| $(d)$ Degree of dissociation of electrolyte | $(iv)$ $\Omega^{-1} \,\mathrm{~m}^{-1}$ |
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The major product obtained on treatment of
$CH_3CH_2CH(F)CH_3$ with $CH_3O^-/CH_3OH$ is
→$CH_3CH_2CH(F)CH_3$ with $CH_3O^-/CH_3OH$ is
$\begin{matrix}
C{{H}_{3}}-CH-C{{H}_{3}} \\
\,|\,\,\,\,\,\,\,\,\, \\
OH\,\,\, \\
\end{matrix}$$\xrightarrow{PB{{r}_{3}}}A\xrightarrow{Mg}B\xrightarrow{\begin{matrix}
O\,\, \\
/\,\,\,\,\backslash \, \\
C{{H}_{2}}-\,C{{H}_{2}} \\
\end{matrix}}C$ $\xrightarrow{{{H_2}O}}D$ Here, $D$ is
→C{{H}_{3}}-CH-C{{H}_{3}} \\
\,|\,\,\,\,\,\,\,\,\, \\
OH\,\,\, \\
\end{matrix}$$\xrightarrow{PB{{r}_{3}}}A\xrightarrow{Mg}B\xrightarrow{\begin{matrix}
O\,\, \\
/\,\,\,\,\backslash \, \\
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Dimethyl glyoxime gives a red precipitate with $N{i^{2 + }},$ which is used for its detection. To get this precipitate readily the best $pH$ range is
→The number of chiral centres present in $[ B ]$ is
→The $IUPAC$ name of $CH_3CH_2OCH(CH_3)_2$ is
→An element of atomic number $29$ belongs to
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→The dipole moment of $HBr$ is $1.6 \times {10^{ - 30}}\,cm$ and interatomic spacing is $1\,\mathop A\limits^o $. The $\%$ ionic character of $HBr$ is
→Correct order of bond angle in given species is