MCQ
Select the diamagnetic coloured compound:-
- A$AgI$
- B$KMnO_4$
- C$I_2$
- ✓All of these
$\mathrm{I}_{2}=$ due to Homo-Lumo
$\mathrm{AgI}=$ polarisation
$\mathrm{KMnO}_{4}=$ charge transfer
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$\mathrm{Sn}(\mathrm{s})\left|\mathrm{Sn}^{2+}(\mathrm{aq}, 1 \mathrm{M}) \| \mathrm{Pb}^{2+}(\mathrm{aq}, 1 \mathrm{M})\right| \mathrm{Pb}(\mathrm{s})$
the ratio $\frac{\left[\mathrm{Sn}^{2+}\right]}{\left[\mathrm{Pb}^{2+}\right]}$ when this cell attains equilibrium is
(Given $\mathrm{E}_{\mathrm{Sn}^{2+} / \mathrm{Sn}}^{0}=-0.14 \mathrm{\;V}$ $\left.\mathrm{E}_{\mathrm{Pb}^{+2}/{\mathrm{Pb}}}^{0}=-0.13 \;\mathrm{V}, \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.06\right)$
Reason : $NF_3$ ionizes to give $F^-$ ions in aqueous solution.