MCQ
Select the INCORRECT relation.
- ✓$pOH = pK_b - log_10 ([salt])/([base])$
- BpH + pOH = 14
- C$p \mathrm{~K}_{\mathrm{b}}=-\log _{10} \mathrm{~K}_{\mathrm{b}}$
- D$\mathrm{K}_{\mathrm{w}}=\left[\mathrm{H}_3 \mathrm{O}^{+}\right]\left[\mathrm{OH}^{-}\right]$