Question
Select the incorrect statement

Answer

d
In ionic compounds as internuclear distance increases, the melting point decreases so as we move down the group, the melting point decreases.

So, as $r_c+r_a$ is greater for $RbBr$ than for $NaF$ so $NaF$ have higher melting point.

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$(1)$ $C{H_3}C{H_2}C{H_2}Cl + $ $\begin{array}{*{20}{c}}
  {\,\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ 
  {\,\,\,|} 
\end{array}} \\ 
  {C{H_3} - C - {O^ - }} \\ 
  {\,\,\,|} \\ 
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\end{array}$                      $(2)$  $C{H_3}C{H_2}C{H_2}I + $$\begin{array}{*{20}{c}}
  {\,\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ 
  {\,\,\,|} 
\end{array}} \\ 
  {C{H_3} - C - {O^ - }} \\ 
  {\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}$

$(3)$  $\begin{array}{*{20}{c}}
  {{H_3}C - CH - C{H_3}} \\ 
  {|\,\,\,\,} \\ 
  {Br\,\,\,} 
\end{array}$  $+CH_3O^-$                      $(4)$  $\begin{array}{*{20}{c}}
  {{H_3}C - CH - C{H_3}} \\ 
  {|\,\,\,\,} \\ 
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