MCQ
Select the odd one
- A$4f$
- B$5d$
- ✓$3s$
- D$4p$
$4 f \Rightarrow 4+3=7$
$5 d \Rightarrow 5+2=7$
$3 s \Rightarrow 3+0=3$
$6 p \Rightarrow 6+1=7$
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$\begin{array}{*{20}{c}}
{C{H_2} - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2} - COOH}
\end{array}\xrightarrow{\Delta }(A)\xrightarrow{{C{H_3} - C{H_2}N{H_2}/\Delta }}(B)$
$(B)$ will be :