- A${H_3}{O^ + },HPO_4^{ - 2},HCO_3^ - $
- B${H_2}O,HPO_3^{ - 2},{H_2}PO_2^ - $
- ✓${H_2}PO_4^ - ,{H_2}PO_3^ - ,{H_2}O$
- DAll of these
Amphiprotic species can behave both like an acid and a base. They can donate or accept a proton.
$\underset{\text { Conjugate acid }}{ H _3 PO _4} \stackrel{+ H ^{+}}{\longleftarrow} \underset{\text { Amphiprotic }}{\stackrel{ H _2 PO _4^{-}}{ }} \stackrel{- H ^{+}}{\longrightarrow} \underset{\text { Conjugate base }}{ HPO _4^{2-}}$
$\underset{\text { Conjugate acid }}{ H _3 PO _3} \stackrel{+ H ^{+}}{\longleftarrow} \underset{\text { Amphiprotic }}{ H _2 PO _3^{-}} \stackrel{- H ^{+}}{\longrightarrow} \underset{\text { Conjugate base }}{ HPO _3^{2-}}$
$\underset{\text { Conjugate acid }}{ H _3 O ^{+}} \stackrel{+ H ^{+}}{\longleftarrow} \underset{\text { Amphiprotic }}{ H _2 O} \stackrel{- H ^{+}}{\longrightarrow} \underset{\text { Conjugate base }}{ OH ^{-}}$
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Assertion $A$: Helium is used to dilute oxygen in diving apparatus.
Reason $R:$ Helium has high solubility in $O _2$.
In the light of the above statements, choose the correct answer from the options given below
$(A)$ Addition of an electron in $O_2$ decreases bond order
$(B)$ Addition of an electron in $O_2$ increases bond order
$(C)$ Removal of an electron from $O_2$ increases bond length
$(D)$ Removal of an electron from $O_2$ decreases bond length