Question
Shobhit's father wants to construct a rectangular garden using a brick wall on one side of the garden and wire fencing for the other three sides as shown in figure. He has $200\  ft$ of wire fencing.

Based on the above information, answer the following questions.
  1. To construct a garden using $200 \ ft$ of fencing, we need to maximise its.
  1. Volume
  2. Area
  3. Perimeter
  4. Length of the side
  1. If $x$ denote the length of side of garden perpendicular to brick wall and $y$ denote the length of side parallel to brick wall, then find the relation representing total amount of fencing wire.
  1. $x + 2y = 150$
  2. $x + 2y = 50$
  3. $y + 2x = 200$
  4. $y + 2x = 100$
  1. Area of the garden as a function of $x,$ say $A(x),$ can be represented as.
  1. $200 + 2x^2$
  2. $x - 2x^2$
  3. $200x - 2x^2$
  4. $200 - x^2$
  1. Maximum value of $A(x)$ occurs at $x$ equals.
  1. $50 \ ft$
  2. $30 \ ft$
  3. $26 \ ft$
  4. $31 \ ft$
  1. Maxi mum area of garden will be.
  1. $2500 \ sq. ft$
  2. $4000 \ sq. ft$
  3. $5000 \ sq. ft$
  4. $6000 \ sq. ft$

Answer

  1. $(b)$ Area
To create a garden using $200 \ ft$ fencing, we need to maximise its area.
  1. $(c) y + 2x = 200$
Required relation is given by $2x + y = 200.$
  1. $(c) 200x - 2x^2$
Area of garden as a function of $x$ can be rep resented as 
$A(x) = x·y $
$= x(200 - 2x) $
$= 200x - 2x^2$​​​​​​​
  1. $(a) 50 \ ft$
$A(x) = 200x - 2x^2 $
$\Rightarrow (x) = 200 - 4x$
For the area to be maximum $A\ '(x) = 0$
$\Rightarrow 200 - 4x =0$
$\Rightarrow x = 50 \ ft​​​​​​​$
  1. $(c) 5000 \ sq. ft$
Maximum area of the garden $= 200(50) - 2(50)^2 $
$= 10000 - 5000 $
$= 5000 \ sq. ft$

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  1. $\ce{c(h) = 100h - 320 - 1600/ h}$
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  3. $\ce{c(h) = 100 + 320h + 1600h^2}$
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  2. $5$
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