Question
Show that $1 – 2sin θ cos θ ≥ 0$ for all $θ ∈ R.$

Answer

$1 – 2 \sin \theta \cos \theta $
$= \sin^2 \theta + \cos^2 \theta – 2sin \theta \cos \theta $
$= (\sin \theta – \cos \theta )^2 \geq 0$ for all $θ ∈ R$

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