Question
Show that $ :35^3+ 27^3$ is divisible by $62$

Answer

$(35^3+ 27^3)$
[Using identity $(a^3+ b^3)=(a + b)(a^2-ab+ b^2)]$
$= ( 35 + 27 )( 35^2+ 35\times 27 + 27^2)$
$= 62 \times ( 35^2+ 35 \times 27 + 27^2)$
Therefore, the number is divisible by $62.$

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