Question
Show that: $(4 p q+3 q)^2-(4 p q-3 q)^2=48 p q^2$

Answer

$(4 p q+3 q)^2-(4 p q-3 q)^2=48 p q^2$
LHS $= (4pq + 3q)^2- (4pq - 3q)^2$
$= 4(4pq) (3q) [∵(a + b)^2- (a + b)^2= 4ab]$
$= 48pq^2$
= RHS

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