Question
Show that:
$(9 a-5 b)^2+180 a b=(9 a+5 b)^2$

Answer

$(9 a-5 b)^2+180 a b=(9 a+5 b)^2$
$LHS= (9a - 5b)^2+ 180ab$
$= (9a + 5b)^2$ $ [∵(a + b)(a - b) = a^2- b^2]$
$= RHS$
Because $LHS$ is equal to $RHS,$ the given equation is verified.

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