Algebraic Expressions and Identities — Maths STD 8 — Question
Maharashtra BoardEnglish MediumSTD 8MathsAlgebraic Expressions and Identities2 Marks
Question
Show that:
$(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0$
✓
Answer
$(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0$
$\text { LHS }=(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)$
$=a^2-b^2+b^2-c^2+c 2-a^2$
$=0$
$=\text { RHS }$
Because LHS is equal to RHS, the given equation is verified.
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