Show that C_0+C_1+C_2+ . .+C_8=256 - Vidyadip

Question

Show that $C_0+C_1+C_2+\ldots . .+C_8=256$

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Answer

Since $C_0+C_1+C_2+C_3+\ldots . .+C_n=2^n$
Putting n = 8, we get
$C_0+C_1+C_2+\ldots . .+C_8=2^8$
$\therefore C_0+C_1+C_2+\ldots . .+C_8=256$

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