Question
Show that for any sets A and B,$\text{A}=(\text{A}\cap\text{B})\cap(\text{A - B})$

Answer

We know that $(\text{A}\cap\text{B})\subset\text{A and (A - B)}\subset\text{A}$ $\Rightarrow(\text{A}\cap\text{B})\cap(\text{A - B})\subset\text{A}......(\text{i})$ Let and $\text{x}\in(\text{A}\cap\text{B})\cap(\text{A - B})$ $\Rightarrow\text{x}\in(\text{A}\cap\text{B})\text{ and x}\in(\text{A}-\text{B})$ $\Rightarrow\text{x}\in\text{A and}\text{ x}\in\text{B and }\text{x}\in\text{A and }\text{x}\not\in\text{B}$ $\Rightarrow\text{x}\in\text{A and }\text{x}\in\text{A}$ [$\because\text{ x}\in\text{A}\text{ x}\not\in\text{A}$ are not possible simutaneusly] $\Rightarrow\text{x}\in\text{A}$ $\therefore(\text{A}\cap\text{B})\cap\text{(A - B)}\subset\text{A}..........\text{(ii)}$ From (i) and (ii), we get $\text{A}=(\text{A}\cap\text{B})\cap(\text{A - B}).$

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