Question
Show that, for any vectors $\bar{a}, \bar{b}, \bar{c}$

$(\bar{a}+\bar{b}+\bar{c}) \times \bar{c}+(\bar{a}+\bar{b}+\bar{c}) \times \bar{b}+(\bar{b}+\bar{c}) \times \bar{a}=2 \bar{a} \times \bar{c}$

Question is modified.

For any vectors $\bar{a}, \bar{b}, \bar{c}$ show that

$(\bar{a}+\bar{b}+\bar{c}) \times \bar{c}+(\bar{a}+\bar{b}+\bar{c}) \times \bar{b}+(\bar{b}-\bar{c}) \times \bar{a}$

$=2 \bar{a} \times \bar{c}$.

Answer

$\begin{aligned} & \text { LHS }=(\bar{a}+\bar{b}+\bar{c}) \times \bar{c}+(\bar{a}+\bar{b}+\bar{c}) \times \bar{b}+(\bar{b}-\bar{c}) \times \bar{a} \\ & =\bar{a} \times \bar{c}+\bar{b} \times \bar{c}+\bar{c} \times \bar{c}+\bar{a} \times \bar{b}+\bar{b} \times \bar{b}+\bar{c} \times \bar{b}+\bar{b} \times \bar{a}-\bar{c} \times \bar{a} \\ & =\bar{a} \times \bar{c}+\bar{b} \times \bar{c}+\overline{0}+\bar{a} \times \bar{b}+\overline{0}-\bar{b} \times \bar{c}-\bar{a} \times \bar{b}+\bar{a} \times \bar{c}\end{aligned}$

$\ldots[\because \bar{a} \times \bar{b}=-\bar{b} \times \bar{a}]$

$=2 \bar{a} \times \bar{c}=\mathrm{RHS}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free