Question
Show that f(x) = e2x is increasing on R.
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$\frac{dy}{dx} + 2y = \text6 {e^{x}}$
$\tan^{-1}\Bigg(\frac{1}{3}\Bigg)+\tan^{-1}\Bigg(\frac{1}{5}\Bigg)+\tan^{-1}\Bigg(\frac{1}{7}\Bigg)+\tan^{-1}\Bigg(\frac{1}{8}\Bigg)=\frac{\pi}{4}.$
f : R → R, defined by f(x) = 3 - 4x