Question
Show that in a cubic close packed structure, eight tetrahedral voids are present per unit cell.

Answer

In ccp, each cube consists of eight cubic components. Number of atoms per unit cell in ccp is $N_c \times$ contribution + $N_f​ \times$ contribution $8\times\frac{1}{6}+6\times\frac{1}{2}=4$

Position of tetrahedral Voids = At the centre of each cubic component Number of tetrahedral voids per unit cell in cubic close packing = 8 × 1 = 8 Number of tetrahedral Voids = 8.

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