Dual Nature of Radiation and Matter — Physics STD 12 Science — Question

We get, $\frac{\text{hc}}{\lambda}+\text{m}_0\text{c}^2=\text{mc}^2$

and applying conservation of momentum $\frac{\text{h}}{\lambda}=\text{mv}$

Mass of e $=\text{m}=\frac{\text{m}_0}{\sqrt{1-\frac{\text{v}^2}{\text{c}^2}}}$

from above equation it can be easily shown that

V = C

V = 0

both of these results have no physical meaning hence it is not possible for a photon to be completely absorbed by a free electron.