Question
Show that the following points are collinear using determinants : L(2, 5), M(5, 7), N(8, 9)
$\begin{aligned} & \mathrm{M}\left(\mathrm{x}_2, \mathrm{y}_2\right)=\mathrm{M}(5,7) \\ & \mathrm{N}\left(\mathrm{x}_3 \mathrm{y}_3\right)=\mathrm{N}(8,9)\end{aligned}$
If A(ΔLMN) = 0, then the points L, M, N are collinear.
$A(\Delta L \mathrm{LN})=\frac{1}{2}\left|\begin{array}{lll}2 & 5 & 1 \\ 5 & 7 & 1 \\ 8 & 9 & 1\end{array}\right|$
$=\frac{1}{2}[2(7-9)-5(5-8)+1(45-56)]$
$=\frac{1}{2}[2(-2)-5(-3)+1(-11)]$
$=\frac{1}{2}(-4+15-11)=0$
∴ The points L, M, N are collinear.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.