Question
Show that the function f : R $\rightarrow$ R given by f(x) = x3 is injective.

Answer

Let x1, x2 $\in$ R be such that f(x1) = f(x2)
$ \Rightarrow x_1^3 = x_2^3$
$\Rightarrow$ x1 = x2
Therefore, f is one-one function, hence f(x) = x3 is injective.

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