Question
Show that the function $f(x) = x^3 + 10x + 7$ for $x \in R$ is strictly increasing
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$\sqrt[3]{1+\left(\frac{d y}{d x}\right)^2}=\frac{d^2 y}{d x^2}$
(i) $\cos 2 \theta=\frac{1}{3}$
$\frac{d^2 y}{d x^2}+5 \frac{d y}{d x}+y=x^3$